Use the discriminant of the following quadratic equation to state the number and type of solutions. 3x^ (2) + 4x-5=3x+2

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Mathematics

Maurice Lang

4 October, 05:49

Use the discriminant of the following quadratic equation to state the number and type of solutions. 3x^ (2) + 4x-5=3x+2

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Lana Lyons · Answer 1

3x^ (2) + 4x-3x-5-2=0

3x^ (2) + x-7=0

Discriminat = b^ (2) - 4ac = 1^ (2) - 4 (3) (-7) = 1-12 (-7) = 1+84=85

The discrimination is bigger than 0 (delta>0) therefore there are 2 real solutions