The equation h (t) = - 16 t 2 + 19t+110 gives the height of a rock, in feet, t seconds after it is thrown from a cliff. What is the initial velocity when the rock is thrown? Enter your answer in the box.

For this case we have an equation of the form:

h (t) = (1/2) * a * t ^ 2 + vo * t + h0

Where,

a: acceleration

vo: initial speed

h0: initial height

t: time

We have then that the equations:

h (t) = - 16t ^ 2 + 19t + 110

Therefore, the initial velocity is given by:

vo = 19 feet / s

Answer:

The initial velocity when the rock is thrown is:

vo = 19 feet / s