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3 January, 12:56

What is the sum of the first 2018 positive integers?

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  1. 3 January, 15:21
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    Positive integers normally form an arithmetic sequence such that in this case the initial term is 1 and the common difference is 1.

    The number of terms is 2018 and therefore n = 2018

    Sn = n/2 (2a + (n-1) d) where Sn is the sum of n terms, a is the first term and d is the common difference.

    Substituting the unknowns with the values

    we get Sn = 2018/2 (2 + (2017) 1)

    = 2018 / 2 (2019)

    = 4074342/2

    = 2037171

    Therefore the sum of the first 2018 positive integer is 2037171.
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