Given: ΔACM, m∠C = 90º

CP

⊥

AM

, AC = 15

AP = 9, PM = 16

Find: CP, CM

CP=12, CM=20. CP is the altitude of the triangle. ACP is a right triangle, so you can solve for CP using Pythagorean's theorem. CP=/sqrt (AC^2-CP^2) = / sqrt (15^2-9^2) = 12. AM=AP+PM=9+16=25. Triangle ACM is another right triangle, and CM=/sqrt (AM^2-AC^2) = / sqrt (25^2-15^2) = 20.