Find the value of z such that 0.96420.9642 of the area lies between - z-z and z. round your answer to two decimal places.

If z represents the variable of the standard normal distribution curve N (0,1), which is symmetrical about z=0, then we look for

P (z) - P (-z) = 0.9642=1-2P (-z) = > P (-z) = (1-0.9642) / 2=0.0179

=>

-z=-2.099192

=> z=2.099192

Check:

P (2.099192) - P (-2.099192) = 0.9642 ok