Solve the system below using any method:

X+2y=1

5x-4y=-23

I'll use substitute method.

x + 2y = 1. (1)

5x - 4y = - 23. (2)

from 1,

x = 1 - 2y. (3)

then I'll substitute (3) into 2,

5 (1-2y) - 4y = - 23. (this way we only need to calculate y, as x is isolated out)

5 - 10y - 4y = - 23

5 - 14y = - 23

-14y = - 28

y = 2

now we can substitute y = 2 back into (3)

x = 1 - 2 (2)

x = - 3

therefore we get that x is - 3 and y is 2.

X+2y=1

2y = 1-x

y = (1-x) / 2

5x-4y = - 23

By substituting the value of y in this equation

5x - 4 { (1-2) / 2} = - 23

5x - 2 + 2x = - 23

7x = - 21

x = - 3

Now, let's find the value of y bu putting the value in any othe two equations

I'll use x + 2y=1

-3 + 2y=1

2y = 4

y=2

So, the value of x and y is - 3 and 2 respectively.