What is the standard deviation of the following data set rounded to the nearest tenth?

51.8, 53.6, 54.7, 51.9, 49.3

A. 3.4

B. 3.3

C. 1.9

D. 1.8

51.8, 53.6, 54.7, 51.9, 49.3

the standard deviation of the data set will be found as follows:

Var = ∑ (x-μ) ² / (n)

μ-mean

μ = (51.8+53.6+54.7+51.9+49.3) / 5

μ=261.3/5=52.26

Next:

∑ (x-μ) ² = (51.8-52.26) ² + (53.6-52.26) ² + (54.7-52.26) ² + (51.9-52.26) ² + (49.3-52.26) ²

∑ (x-μ) ²=16.852

thu

Var (x) = 16.852 / (5) = 3.3704

Hence the standard deviation will be:

σ=√3.3704=1.835865~1.8

Answer: D] 1.8