Solve the system. 4x+2y=4 6x-8=-2y

4x + 2y = 4

6x - 8 = - 2y

Both equations are divisible by 2, so divide both sides of both equations by 2.

2x + y = 2

3x - 4 = - y

Since the second equation has - y on one side, we can multiply both sides by - 1 to solve for y.

y = - 3x + 4

Now we substitute y of the first equation with - 3x + 4.

This is the substitution method.

2x + y = 2

2x - 3x + 4 = 2

-x + 4 = 2

-x = - 2

x = 2

Now we substitute 2 for x in the first original equation and solve for y.

4x + 2y = 4

4 (2) + 2y = 4

8 + 2y = 4

2y = - 4

y = - 2

The solution is x = 2 and y = - 2