The table represents the start of the division of - 2x^3+11x^2-23x+20 by x^2-3x+4

Not sure what the question is, but the quotient is - 2x+5.

We first look for the number of times x² goes into - 2x³. It goes in - 2x times. This goes over - 23x in the box. Multiply back by the divisor, and the product we write under the dividend in the box is

-2x³+6x²-8x

We now have this subtraction:

-2x³+11x²-23x

- (2x³ + 6x² - 8x)

Which gives us

5x²-15x

Bring down the 20 from the dividend and we have

5x²-15x+20

Now we see how many times x² will go into 5x². It goes 5 times, so we write + 5 beside our - 2x in the quotient. Multiply 5 by the divisor, and we have the following to write under the next line in our process:

5x²-15x+20

When we subtract this from the previous line, we have 0 remainder.