Evaluate ∫ e3x dx. A. e3x + C B. 1 / e4x+C 4 C. e4x + C D. 1/3 e3x + C

Since the integral of (e^ax) dx = (1/a) (e^ax) + C, then in this case, we can let a = 3, and follow the formula to integrate this.

integral of (e^3x) dx = (1/3) (e^3x) + C, where C is an arbitrary constant.

This is choice D.