A cylindrical rain barrel with a diameter of 3.5 feet and a height of 5.5 feet is filled to a height of 0.5 feet. How many more gallons of water can the barrel hold? Round your answer to the nearest whole number. (1 ft3≈7.5 gal)

The volume of the barrel is given by:

V1 = (pi) * (r ^ 2) * (h)

Where,

r: barrel radio

h: height of the barrel

Substituting values we have:

V1 = (3.14) * ((3.5 / 2) ^ 2) * (5.5)

V1 = 52.89 feet ^ 3

The volume of the barrel up to a height of 0.5 feet is given by:

V2 = (3.14) * ((3.5 / 2) ^ 2) * (0.5)

V2 = 4.81 feet ^ 3

Subtracting both volumes we have:

V1-V2 = 52.89 - 4.81

V1-V2 = 48.08 feet ^ 3

In gallons we have:

V1-V2 = (48.08) * (7.5)

V1-V2 = 360.6 gallons

Round to the nearest whole number:

V1-V2 = 361 gallons

Answer:

the barrel can hold 361 more gallons