Which is the percent composition of bromine in the compound nabr?

a. 77.7%

b. 81.6%

c. 79.9%

d. 84.1%?

We are given a compound known to be Sodium Bromine (NaBr). This compound has a molecular weight of

Na=23 g/mol and Br=80 g/mol

NaBr=23+80 = 103 g/mol

Assuming if we have 1 mol of NaBr, then we have 80 g of Bromine (Br). Calculating its percent composition in the total NaBr compound, we get

%Br = (80/103) * 100=77.7%

Therefore, the answer to the question above is letter A.