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13 June, 04:25

The 12th term of an arithmetic sequence is 36, and the common difference is 3. What is the first term of the sequence?

A. 1

B. 2

C. 3

D. 4

+3
Answers (2)
  1. 13 June, 05:59
    0
    An=a1+d (n-1)

    d=3

    a12=36

    a12=a1+3 (12-1)

    36=a1+3 (11)

    36=a1+33

    minus 33 both sides

    3=a3

    C is answer
  2. 13 June, 07:02
    0
    The answer is c on edgunity
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