Two similar parallelograms have areas 125 m 2 and 80 m 2. the height of the larger parallelogram is 10 m. what are the lengths of the bases of both parallelograms? solved

To solve this problem you must follow the proccedure shown below:

You have that:

- Two similar parallelograms have areas 125 m².

- The height of the larger parallelogram is 10 m. Then, you have:

125=10x

x: the base of the larger parallelogram

x=125/10

x=12.5 m

The ratio is:

b/h=12.5/10

b=1.25h

- The area of the smaller parallelogram is 80 m ², then, you have:

80=bh

When you susbstitute b=1.25h into 80=bh, you obtain the value of "h":

80 = (1.25h) h

80=1.25h ²

h=√ (80/1.25)

h=8

Then, the other base is:

b=1.25 (8)

b=10 m

The answer is: The base of the smaller parallelogram is 10 m and the base of the larger parallelogram is 8 m.