How to solve using substitution y=3/4x+5 and 4x-3y=-1

So, since we know what is y = to. we are going to plug in that equation for y I n the 2nd equation.

for example:

y=3/4x+5

4x-3 (3/4x+5) = - 1

4x-9/4x+15=-1

16/4x-9/4x=-16

5/4x=-16

multiply by the reciprocal on both sides toget x.

4/5 (5/4x) = (-16) 4/5

x = - 64/5 = - 12 and 4/5ths