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22 December, 07:24

F (x) = x4/5 (x - 6) 2 find the critical numbers of the function

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  1. 22 December, 11:04
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    You can find the critical numbers by finding the derivative of the function and solving for 0.

    F (x) = x (4/5) (x-6) (2) = x (8/5) (x-6) = (8/5) (x^2 - 6x)

    Taking the derivative:

    F' (x) = (8/5) (2x - 6)

    F' (x) = 0 at x = 3,

    critical number = 3
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