Two opposite sides of a square with length x are increased by 3 units each and the other two opposite sides are decreased by 3 units each. If the area of the resulting rectangle is 27 unit^2, what would be the width of the rectangle? Hint: area of rectangle = length * width

A 3

B 6

C 9

D - 3

E - 6

Question

Mathematics

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24 May, 19:24

Two opposite sides of a square with length x are increased by 3 units each and the other two opposite sides are decreased by 3 units each. If the area of the resulting rectangle is 27 unit^2, what would be the width of the rectangle? Hint: area of rectangle = length * width

A 3

B 6

C 9

D - 3

E - 6

+2

Answers (1)

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Avah Oconnell · Answer 1

All four sides of the original square have length s.

Adding 3 to s results in s+3, the length of the resulting rectangle.

Subtracting 3 from s results in s-3, the width of the rectangle.

The area of the rectangle is (s+3) (s-3) = s^2 - 9 = 27,

and therefore s^2 = 36, and s = 6 square units.

Two opposite sides of a square with length x are increased by 3 units each and the other two opposite sides are decreased by 3 units each. If the area of the resulting rectangle is 27 unit^2, what would be the width of the rectangle? Hint: area of rectangle = length * widthA 3B 6C 9D - 3E - 6