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9 February, 22:39

How do you factor - 27x^3-8

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  1. 10 February, 02:12
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    Recognize that there are several cubes here.

    27x^3-8 = 3^3*x^3 - 2^3, which is the same as (3x) ^3 - 2^3

    This latter result is the difference of cubes, and thus it can be factored further as follows:

    [ (3x) - 2 ][ (3x) ^2 + 6x + 4]
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