A bag contains 6 blue balls, 3 green balls and 3 yellow balls. What is the probability of choosing one blue ball and then a yellow ball with replacement?

Question

Mathematics

Cheese

2 February, 17:37

A bag contains 6 blue balls, 3 green balls and 3 yellow balls. What is the probability of choosing one blue ball and then a yellow ball with replacement?

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Answers (1)

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Kamari Myers · Answer 1

Prob (first ball being blue) = 6 / (6 + 3 + 3) = 6/12 = 1/2

Prob (picking a yellow ball) = 3 / 12 = 1/4

As the 2 events are independent the probabilities are multiplied

So the answer is 1/2 * 1/4 = 1/8