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12 December, 09:01

The equation of a circle whose center is at (4, 0) and radius is length 2√ (3) is (x - 4) ² + y² = 2√3 (x - 4) ² + y² = 12 (x + 4) ² + y² = 12

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  1. 12 December, 10:21
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    The equation of a circle is (x-a) ² + (y-b) ²=R²

    (x-4) ² + (y-0) ² = (2√3) ²

    (x-4) ²+y²=12
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