A bacteria population is 6000 at time t = 0 and its rate of growth is 1000 · 9t bacteria per hour after t hours. what is the population after one hour? (round your answer to the nearest whole number.)

dP/dt = 1000 * 9^t is the bacteria population's growth rate. where:P (t) is the population at time t, andP (0) = 6000.

The population after one hour would be:

P (1) = P (0) +

P (1) = P (0) + [ 1000 * 9^1 / ln (9) - 1000 * 9^0 / ln (9) ]

P (1) = 6000 + 3641 = 9461 would be the answer