The square of a number exceeds that number by 12. What are the two possible solutions?

3 or - 4

3 or 4

-3 or 4

Question

Annabel Clayton

29 July, 16:10

+4

Answers (2)

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Braelyn Shaffer · Answer 1

X^2=x+12

minus x+12 both sides

x^2-x-12=0

factor

(x-3) (x+4) = 0

set each to zero

x-3=0

x=3

x+4=0

x=-4

x=3 or - 4

answer is first one

Eden Donaldson · Answer 2

The square of a number exceeds that number by 12. What are the two possible solutions would e B i think

The square of a number exceeds that number by 12. What are the two possible solutions?3 or - 43 or 4-3 or 4