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20 May, 06:37

How to solve 45 45 90 triangle given hypotenuse?

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  1. 20 May, 07:32
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    From the Special Triangle Theorem, the hypotenuse is equal to the side lengtht times the Sqrt (2).

    So hypotenuse H = xSqrt (2), x=H/Sqrt (2).

    Using numbers, if H = 7, then x = 7/Sqrt (2) = 7Sqrt (2) / 2 to rationalize it.
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