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13 October, 11:24

Some bullfrogs were introduced into a small pond. The graph shows the bullfrog population for the next few years. Assume that the population grows exponentially.

equation: 140 (315/140) ^ (t/2)

What is the growth rate?

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  1. 13 October, 15:11
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    For exponential growths,

    population after time t = original population x (growth rate) ^time

    The growth rate works out to be:

    (315/140) ^ (t/2)

    = [√ (315/140) ]^t

    = 1.5^t

    The growth rate is 1.5 times per year.
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