Step by step how to factor:

2y^2+9y+9=0

Use ac method

for ax²+bx+c=0 when a≠1

multiply a and c, let's call the product r

what 2 numbesr multiply to get r and add to get b

2y²+9y+9=0

2*9=18

wat 2 numbers multiply to get 18 and add to get 9

3 and 6

split it up to that

2y²+3y+6y+9=0

group

(2y²+3y) + (6y+9) = 0

factor

y (2y+3) + 3 (2y+3) = 0

undistribute

(y+3) (2y+3) = 0

set to zero

y+3=0

y=-3

2y+3=0

2y=-3

y=-3/2

y=-3 and - 3/2

it's factored form is (x+3) (2x+3)