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19 September, 22:32

Find all values of k so that each trinomial

2 x^2 + kx+12

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Answers (1)
  1. 20 September, 01:52
    0
    K can be 10,11,14,25

    Work

    (2x+4) (X+3)

    (2x+3 (X+4)

    (2x+6) (X+2)

    (2x+2) (X+6)

    (2x+1) (X+12)

    (2x+12) (X+1)
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