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13 April, 23:06

Find the equation of the axis of symmetry and the coordinates of the vertex of the graph of the following function. y=x^2-6x-4

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  1. 14 April, 00:41
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    The coordinates of the vertex are (3, - 13) and the axis of symmetry is at x = 3.

    We can find the vertex by using the formula for finding x-coordinates. The formula for the x-coordinate of a vertex is below.

    -b/2a

    In this equation, a is the coefficient of the x^2 term (1) and b is the coefficient of the x term (-6). Then we can plug in to find the x term.

    - (-6) / 2 (1)

    6/2

    3

    Now that we have this term, we can plug it in for all values of x to find the y term.

    x^2 - 6x - 4

    3^2 - 6 (3) - 4

    9 - 18 - 4

    -13

    Now we know that the vertex is at (3, - 13). Now finding the axis of symmetry is easy because the axis of symmetry in any quadratic is simply x = [x-coordinate of vertex]. So in this case it would be x = 3.
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