The bases on a baseball diamond are 90 feet apart. how far is it from home plate to second base?

See diagram

so we got a right triangle

so for a right triangle, when we've got legs a and b and hytponuse c then

a²+b²=c²

so the legs are 90 and 90

hytponuse is distance from home to 2nd

so

90²+90²=c²

8100+8100²=c²

16200=c²

sqrt both sides

90√2=c

aprox

127.279ft

about 127ft

Assuming that the bases are all within right angles of each other:

Form a triangle with vertices at home base, first, and second. Home to first is 90ft and first to second is also 90ft.

Use the formula a^2+b^2=c^2 to find the the missing length.

90^2+90^2=c^2

8100+8100=c^2

16200=c^2

Sqrt (16200) = c

c=127.279