There were 27,000 people at a ball game in Los Angeles. The day's receipts were $204,000. How many people paid $13 for reserved seats and how many paid $6 for general admission?

Question

Mathematics

Rashad Brady

6 January, 02:06

There were 27,000 people at a ball game in Los Angeles. The day's receipts were $204,000. How many people paid $13 for reserved seats and how many paid $6 for general admission?

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Answers (1)

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Viviana Ingram · Answer 1

21000 people paid for general admission and 6000 paid for reserved seats. This is solved by making 2 equations. Out of 27000 people who were at game, x of them paid for general admission and y for reserved seats, thus

x + y = 27000

As said, daily receipts were 204000$. As reserved seat is 13$, y of them gave 13$ each (y*13$) and x of them gave 6 for general admission (x*6) and those two add up and we get second equation

13y + 6x = 204000.

This can be solved by transforming first equation into x = 27000 - y and then replacing the x in second.

13y + 6 * (27000 - y) = 204000

13y + 162000 - 6y = 204000

7y = 42000

y = 6000

x + 6000 = 27000

x = 27000 - 6000 = 21000