The sum of three consecutive numbers is twelve less than six times the lowest number. What are the three numbers?

Let one of the number be x.

The other two numbers are x+1 and x+2.

The sum of three consecutive numbers is twelve less than six times the lowest number.

⇒ x + (x+1) + (x+2) - 12 = 6x

⇒ x + x + 1 + x + 2 - 12 = 6x

⇒ 3x + 9 = 6x

⇒ 3x = 9

⇒ x = 3

Find the numbers:

x = 3

x + 1 = 4

x + 2 = 5

Answer : The numbers are 3, 4 and 5