Ask Question
8 January, 10:03

The water level in an inflatable pool decreases by about 6.35*10-16.35*10-1 centimeters each day due to evaporation. There are 8.64*1048.64*104 seconds in a day. About how many centimeters does the water level in the pool decrease each second?

+5
Answers (2)
  1. 8 January, 10:52
    0
    Answer: 7.3*10^-6

    comment if got right or wrong
  2. 8 January, 13:01
    0
    7.35 x 10^-6 cm per second This is an exercise in division using scientific notation. So 6.35x10^-1 / 8.64x10^4 = ? To perform division using scientific notation, you divide the significands as you would normally. So 6.35 / 8.64 = 0.734953704 Then you subtract the exponents. So - 1 - 4 = - 5 Giving you a result of 0.734953704 x 10^-5 Notice that the significand in this case is less than 1. That means that you now need to normalize the result, getting a significand that's greater than or equal to 1 and less than 10. We can do this by multiplying the significand by 10 and then subtracting 1 from the exponent. So 0.734953704 * 10 = 7.34953704 - 5 - 1 = - 6 Giving a new result of: 7.34953704 x 10^-6 And don't forget about significant figures. Since the least precise piece of data we have is 3 digits, we should round the result to 3 digits. So the final answer is 7.35 x 10^-6 cm per second.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The water level in an inflatable pool decreases by about 6.35*10-16.35*10-1 centimeters each day due to evaporation. There are ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers