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27 August, 20:45

Find the taylor series for xex about x = 0. then integrate term-by-term and substitute to show that the series

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  1. 27 August, 22:42
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    The Taylor series for e^x about x = 0 is

    1 + x + x^2/2! + x^3/3! + x^4 / 4! + ...

    xe^x = x + x^2 + x^3/2! + x^4/3! + x^5/4! + ...

    Integrating term by term gives:-

    x^2 / 2 + x^3/3 + x^4 / 3.2! + x^5 / 4.3! + x^6 / 5.4! + ...
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