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11 September, 14:41

Is it possible, for some choice of positive whole numbers m and n, that 63m = 21n? justify your answer?

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  1. 11 September, 15:33
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    Yes, as long as the value of n is three times as big as the value of m.

    We can determine this by dividing the coefficient of n away.

    63m = 21n - - - > divide both by 21.

    3m = n

    To satisfy this, we could use the simple m = 1 and n = 3, which obviously makes the statement true and satisfies our positive whole numbers criteria. We could also use something as large as m = 121 and n = 363.
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