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30 April, 07:37

The sum of a positive interger, x, and its inverse is 4/3. Find the interger

A. 2x^2-4x-390 = 0

B. 3x^2-4x+3 = 0

C. 3x+24=4x+12

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Answers (1)
  1. 30 April, 11:21
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    Starting with the equation:

    x + (1/x) = 4/3

    multiply with x

    x^2 + 1 = (4/3) x

    multiply with 3:

    3x^2 + 3 = 4x

    transfer 4x to the left side of the equation:

    3x^2 - 4x + 3 = 0
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