Find h and k such that the equation 3x^2 - hx + 4k = 0, so that the sum of the solutions is - 12 and the product of the solutions is 20.

Let the solutions be a and b.

a = - 2; b = - 10

a + b = - 2 + (-10) = - 12

ab = (-2) (-10) = 20

(x - a) (x - b) = 0

(x - (-2)) (x - (-10)) = 0

(x + 2) (x + 10) = 0

x^2 + 10x + 2x + 20 = 0

x^2 + 12x + 20 = 0

-h = 12

h = - 12

4k = 20

k = 5