The bases of a right prism are parallelograms with sides a=10 cm, b=6 cm, and altitude of the parallelogram towards side a, ha = 3 cm. Find the surface area of the parallelepiped, if the height of the prism is h=12 cm.

Area of parallelogram = a*h=10*3=30, there are 2 such parallelograms in the prism

2 faces are rectangles with sides 12 and 6,

Area of this face is 12*6=72, there are 2 such faces

2 faces are rectangles with sides 12 and 10

Area of this face is 12*10=120, there are 2 such faces

2*30+2*72+2*120 = 444 cm²