What is the measure of ∠spq in this rhombus? m∠spr = (2x+15) ° m∠qpr = (3x-5) ° enter your answer in the box?

A rhombus is a quadrilateral with fours sides that are equal. The diagonals of a rhombus bisect the angles. In this case PR is a diagonal, such that ∠SPQ is bisected, therefore ∠ SPR = ∠QPR

Thus, 2x + 15 = 3x-5

solving for the value of x,

x=20

Then, ∠SPR = 2 (20) + 15 = 55 and ∠ QPR = 3 (20) - 5 = 55

Therefore, ∠SPQ = ∠SPR + ∠QPR

= 55 + 55 = 110

Hence, the answer is 110