Ask Question
28 April, 03:48

Explain why the graph of quadratic function could not contain both a minimum vertex and a maximum vertex at the same time.

Your explanation should be 3-4 sentences and include at least 6 of the following words/phrase.

-parabola

- u-shaped graph

- vertex

- minimum

- maximum

- y-value of the vertex

- x-value of the vertex

- quadratic function

+3
Answers (1)
  1. 28 April, 07:08
    0
    Start with the general equation of the quadratic in vertex form. It is U shaped and will open upward or downward depending on the value of "a." This particular graph produces a quadratic or a parabola.

    y = a (x - b) ^2 + c

    "a" is the constant that will determine which way the parabola opens. It it is minus, the quadratic has a maximum at (b, c) assuming b and c are both greater than 0.

    If a > 0 then (b, c) is a minimum and the parabola opens upward.

    If a = 0 then the x^2 term does not exist and the parabola does not exist.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Explain why the graph of quadratic function could not contain both a minimum vertex and a maximum vertex at the same time. Your explanation ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers