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1 January, 08:04

Write an equation for a linear function whose graphs has the given characteristics. Passes through (-2,2) and (2,-8)

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  1. 1 January, 10:18
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    (-2,2) (2,-8)

    slope = (-8 - 2) / (2 - (-2) = - 10/4 = - 5/2

    y = mx + b

    slope (m) = - 5/2

    (-2,2) ... x = - 2 and y = 2

    now we sub and find b, the y int

    2 = - 5/2 (-2) + b

    2 = 5 + b

    2 - 5 = b

    -3 = b

    so ur equation is : y = - 5/2x - 3
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