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12 February, 15:26

Write an equation for a linear function whose graph has the given characteristics.

Passes through (42,0), perpendicular to the graph of g (x) = 6x+2

f (x) =

+1
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  1. 12 February, 17:49
    0
    G (x) = 6x + 2 ... the slope here is 6. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal slope, we flip the original slope and change the sign. So our perpendicular line will have a slope of - 1/6. (see how I flipped 6 (or 6/1) and made it 1/6, then I changed the sign and made it - 1/6)

    y = mx + b

    slope (m) = - 1/6

    (42,0) ... x = 42 and y = 0

    now we sub and find b, the y int

    0 = - 1/6 (42) + b

    0 = - 7 + b

    7 = b

    so ur perpendicular equation is : y = - 1/6x + 7 ... or f (x) = - 1/6x + 7
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