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1 May, 06:42

A town's population has been growing linearly. In 2003, the population was 25000, and the population has been growing by 1200 people each year. Write an equation for the population

x

years after 2003.

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Answers (2)
  1. 1 May, 06:58
    0
    Y=25000*1200x

    y would equal the population of the year and x is the amount of years passed.
  2. 1 May, 07:12
    0
    In year 2003 (starting year) it had 25000 pple

    let's say a=25000

    so steadily each year it increases by 1200

    which means the difference between two consecutive years would be 1200 pple

    now this is an arithmetic progression

    using Tx=a + (x-1) 1200

    tx = 25000 + (x-1) 1200

    tx=25000+1200x-1200

    tx = 23800+1200x

    that's the eqn after X years
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