What is the distance between the zeros of the function defined by 6 (2x2+x-8) - 2x (2x-1)

Question

Mathematics

Cisco

31 May, 11:59

What is the distance between the zeros of the function defined by 6 (2x2+x-8) - 2x (2x-1)

+4

Answers (1)

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Shyla Eaton · Answer 1

12x^2+x-8 - (4x^2-1)

12x^2+x-8-4x^2+1

8x^2 + x - 7 = 0

8x^2 + 8x - 7x - 7 = 0

8x (x + 1) - 7 (x + 1) = 0

(8x - 7) (x + 1) = 0

8x - 7 = 0

x + 1 = 0

x = 7/8 and x = - 1