Solve the system of equations

-2x+5y=13

16x+3y=25

-2x + 5y = 13

16x + 3y = 25

To solve this you have to cancel the x first so you multiply the first equation by 8

-2x + 5y = 13. All of that times 8

-16x + 40y = 104

Now that you have this you can cancel x

-16x + 40y = 104

16x. +. 3y. = 25

X cancel

40y = 104

3y. = 25

You add the y and the numbers

43y = 129

/43. / 43

Y = 3

Now you plug y in one of the equations

16x + 3y = 25

16x. + 3 (3) = 25

16x + 9 = 25

-9. - 9

16x = 16

/16. / 16

X = 1

Y = 3 and X = 1

-2x+5y=13

-5 - 5

=8

-2 (negative two)

-2 / 8 = ?

That's how to find answer