The second side of a triangular deck is 3 feet longer than the shortest side and a third side that is 3 feet shorter than twice the length of the shortest side. if the perimeter of the deck is 68 feet, what are the lengths of the three sides?

Question

Mathematics

Draven Grant

1 August, 19:50

The second side of a triangular deck is 3 feet longer than the shortest side and a third side that is 3 feet shorter than twice the length of the shortest side. if the perimeter of the deck is 68 feet, what are the lengths of the three sides?

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Answers (1)

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Amir Osborne · Answer 1

The perimeter of a triangle is:

P = a + b + c

We are given that:

b = a + 3

c = 2 a - 3

Therefore:

68 = a + a + 3 + 2 a - 3

68 = 4 a

a = 17

and,

b = a + 3 = 20

c = 2a - 3 = 31