You are dealt two cards without replacement what is the probability the first card is one of 4 twos and second is 4 tens in a deck

A = drawing a two card

B = drawing a ten card

P (A) = 4/52 = 1/13

P (B|A) = P (A and B) / P (A)

P (A) * P (B|A) = P (A and B)

P (A and B) = P (A) * P (B|A)

P (A and B) = (1/13) * (4/51)

P (A and B) = 4/663

P (A and B) = 0.006033

The answer as a fraction is exactly 4/663

The answer in decimal form is approximately 0.006033