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5 November, 10:59

A rubber ice-hockey puck has a 2.8 in. diameter. What is the surface area of one flat side of the puck? Use π = 3.14. Round to the nearest tenth.

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  1. 5 November, 11:42
    0
    We need to find only the surface of one flat side. This surface is a circle. And surface area formula for a circle is A=r²*π. Since we know the diameter d=2.8 in. The radius is one half of the diameter or: r=d/2=2.8/2=1.4 in. Now we plug this into the formula for the area: A=1.4² * 3.14=1.96 * 3.14=6.1544 in². Rounded to the nearest tenth the area is: A=6.15 in².
  2. 5 November, 14:02
    0
    This is the concept of areas of solid material, we are required to calculate for the area of one side of ice-hockey puck. We know that ice-hockey puck has a cylindrical shape. Thus the area of one flat side will be given by:

    Area=pi (r^2)

    radius=2.8/2=1.4 in

    Area=3.14 (1.4) ^2

    Area=6.1544 in^2
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