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7 January, 04:11

Find the solution of the differential equation (6-8xy2) dy/dx=y3 such that x=2 when y=4 by regarding y as the independent variable rather than x.

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  1. 7 January, 05:47
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    Dy/dx = y³ / (6-8xy²)

    buy x is the dependent variable

    so

    dx/dy = (6-8xy²) / y³ = (6-8*2*16) / 4³

    dx/dy = - 250 / 64 = - 125/32
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