How many extraneous solutions does the equation below have?

9 / (n^2+1) = (n+3) / 4

A) 0

B) 1

C) 2

D) 3

To get the number of solutions we proceed as follows;

9 / (n^2+1) = (n+3) / 4

cross-multiplying the expression we get;

9*4 = (n^2+1) (n+3)

36=n^3+3n^2+n+3

this can be written as:

n^3+3n^2+n-33=0

The above equation a polynomial of degree 3. Therefore we have 3 solutions.

There is 0 solutions I just passed the test