A sum of two numbers is 16 three times the larger number decreased by the smaller number is 72 find the two numbers

Question

Mathematics

Nylah Rhodes

19 May, 12:01

A sum of two numbers is 16 three times the larger number decreased by the smaller number is 72 find the two numbers

+1

Answers (1)

Know the Answer?

Gina · Answer 1

Let a = the larger number

b = the smaller number

a + b = 16

3a - b = 72

a = 16 - b

3 (16 - b) - b = 72

48 - 3b - b = 72

-4b = 24

b = - 6

a = 16 - (-6)

a = 22

The two numbers are:

22 and - 6