Solve for d in the following equation: c (ad) + x=bd+ad (yz)

c (ad) + x=bd+ad (yz) step 1: first we separate x and y, so x=bd+adyz-cad Note: i) (yz) can be written as yz ii) when the term cad comes to right side it becomes - cad, because it is with the addition operation in the left hand side. (it is a general rule of mathematics) step 2: then we take out the common data from the above equation, so the common term for all terms in the right hand side is 'd', so, x=d (b+ayz-ca) step 3: now we need to find d, so d = x/b+ayz-ca Note: the term (b+ayz-ca) becomes the divisor of x since it is in the multiplication term on right hand side. so when moving it to left side, it becomes a division operator. (it is also a general rule of mathematics) so d = x/b+ayz-ca